SRL Archive - Mathematics

So hey guys, this test came up on my test today and am wondering if I did it right:

An area of a square has the equation of 16x^2 - 24x + 9. Find the perimeter of the square.

What I did
Factored the equation into s^2 = A[]

(4x-3)(4x-3) = 16x2 -12x - 12x + 9 = (4x-3)^2

Since the perimeter of a square is 4s, am i correct in doing

(4x-3)(4) = 16x-12

P = 16x - 12?

From: Sin
So hey guys, this test came up on my test today and am wondering if I did it right:

An area of a square has the equation of 16x^2 - 24x + 9. Find the perimeter of the square.

What I did
Factored the equation into s^2 = A[]

(4x-3)(4x-3) = 16x2 -12x - 12x + 9 = (4x-3)^2

Since the perimeter of a square is 4s, am i correct in doing

(4x-3)(4) = 16x-12

P = 16x - 12?

You are correct with this method.

As the area of the square = (4x-3)*(4x-3) where (4x-3) is each side of the square.

This could also be solved using a multivariate calculus approach, but I'm assuming that's beyond this class.

looks about right, basically Sqr(equ)*4