tehq
2013-02-28 16:36:35
Hello,
I shall propose a method for dealing with prime functions.
First off, you must understand what is represented by a characteristic function.
Please refer to this source for further information. (Wolfram)
Now consider the set [1, 2, 3,…,20] for f(n) {1 = prime; 0 = not prime}
The resulting values will be = [0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1]
The binary fraction of these values is approximately = 2/5. However, as n approaches infinity, the binary fraction becomes approximately .41468250985111166(…) I will now refer to this value as Cp.
For every prime less than one million (78,498 primes), the value of n was plotted against 1/Prime(n).
{ Prime(n) = the nth prime }
An extremely strong, negative correlation appears between the values of 1/prime(n) and n. The correlation coefficient for the equation is .9999
The currently calculated equation for the inverse of the nth prime is = .2616*n^(-1.108).
I suggest that the integral of this equation from a lower limit of 1 to an upper limit of infinity will be equivalent to 1/Cp.

Or with a more broad scope, the integral of the inverse of a function to calculate the nth prime from [1, infinity] will be equal to 1/Cp.
Comments?
I shall propose a method for dealing with prime functions.
First off, you must understand what is represented by a characteristic function.
Given a subset A of a larger set, a characteristic function X(a) is defined to be identically one on A, and is zero elsewhere.
Please refer to this source for further information. (Wolfram)
Now consider the set [1, 2, 3,…,20] for f(n) {1 = prime; 0 = not prime}
The resulting values will be = [0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1]
The binary fraction of these values is approximately = 2/5. However, as n approaches infinity, the binary fraction becomes approximately .41468250985111166(…) I will now refer to this value as Cp.
For every prime less than one million (78,498 primes), the value of n was plotted against 1/Prime(n).
{ Prime(n) = the nth prime }
An extremely strong, negative correlation appears between the values of 1/prime(n) and n. The correlation coefficient for the equation is .9999
The currently calculated equation for the inverse of the nth prime is = .2616*n^(-1.108).
I suggest that the integral of this equation from a lower limit of 1 to an upper limit of infinity will be equivalent to 1/Cp.

Or with a more broad scope, the integral of the inverse of a function to calculate the nth prime from [1, infinity] will be equal to 1/Cp.
Comments?