SRL Archive - Help

I get this error:

[Error] C:\Simba\Scripts\Responder.simba(26:34): Type mismatch at line 25

when I try to use this

If Text = (['Hi','Hey','Sup']) Then 

I don't get what im doing wrong

var
  text : string;
begin
  text := 'hi';
  if (text = 'hi') then
    writeln('these strings match');
end.

OT: you can't compare a string to a string array without using a loop.

var
  text : string;
  i : integer;
  texts : TStringArray;
begin
  text := 'hi';
  texts := ['ha', 'he', 'hi'];
  for i := 0 to 2 do
    if (text = texts[i]) then
      writeln('these strings match'); // could break out too
end.

I believe the brackets must be around the entire if statement, because brackets normally imply that whatever's inside them must be calculated first, when doing math for example 3x3x3 vs (3x3)x3, and if you do it the way you did it, I believe the interpreter thinks the array is a bool, so you are trying to conpare a string to a bool, it may work without any brackets, but like Jingle did, Put the brackets around the entire statement and its fine ;)

If that makes any sense :p 3am

If you're trying to see check if Text (which I assume is a string) is one of those three strings, you can use StrInArr. Does just what Jingle said, but it's easier to use.

EDIT:

From: DannyRS
I believe the brackets must be around the entire if statement, because brackets normally imply that whatever's inside them must be calculated first, when doing math for example 3x3x3 vs (3x3)x3, and if you do it the way you did it, I believe the interpreter thinks the array is a bool, so you are trying to conpare a string to a bool, it may work without any brackets…

This isn't correct. Parentheses don't do any type conversion or anything, it just affects precedence. He's getting the error because he's trying to compare a string to an array of string.

Just to show you a comparison, this works fine:

begin
  if [5] = ([6]) then
    Writeln('wat')
  else
    Writeln('ok');
end.

From: i luffs yeww



This isn't correct. Parentheses don't do any type conversion or anything, it just affects precedence. He's getting the error because he's trying to compare a string to an array of string.

Just to show you a comparison, this works fine:

begin
  if [5] = ([6]) then
    Writeln('wat')
  else
    Writeln('ok');
end.

Ah my mistake, didn't see OP was an array, but i'm sure something along the lines of this gave me errors before

If string = (string) Then

Maybe it was using not

If Not string = string Then

Something with a string requires correct brackets, I just can't remember what lol

From: DannyRS
Ah my mistake, didn't see OP was an array, but i'm sure something along the lines of this gave me errors before

If string = (string) Then

Maybe it was using not

If Not string = string Then

Something with a string requires correct brackets, I just can't remember what lol

It must've been something else. Like I said, parentheses by themselves will never change the type of what's inside.

if 'hi' = ('hi') then
  Writeln('true');

All that parentheses are used for is precedence. :)

From: DannyRS

If Not string = string Then

Something with a string requires correct brackets, I just can't remember what lol

Yeah that's probably the cause of your error, since the 'not' keyword takes precedence over all other Boolean operators, which in turn take precedence over all arithmetic operators, hence giving an error as Boolean operators cannot be used on strings in Pascal. (Hence the use of parenthesis to override these orders)

thanks