SRL Archive - Mathematics

I got (5sec(t^2))/2



Any help?

http://www.wolframalpha.com/input/?i=5secxtanx+derivative

You would use the product rule, so 5sec(t) becomes f(x) and tan(t) becomes g(x) and:

(f'*g)+(f*g'), your textbook should provide those derivatives of the individual functions for you.

You're integrating then differentiating? So if you're cunning and want to miss doing all the hard work you'll notice that the only thing you change in the expression is when you substitute your top limit in. And by doing the chain rule when differentiating you know you'll have 2x instead of t, so take that factor of 2 out.

However, this is how you'd normally do it :p:
http://i39.tinypic.com/2hp60w7.jpg

(Dont get confused with the 'x', I used that instead of t)

well I feel retarded