SRL Archive - Mathematics

A question I had in an exam.


Rich

2011-06-07 10:47:22

This is a question which I had in an exam yesterday, which I don't think anyone answered.

There is a hemisphere and a cone.
Both shapes have base radius x.
The shapes both have the same surface area.
Work out the height of the cone (h) in terms of x.

Any idea on how to do it?

x[Warrior]x3500

2011-06-07 11:02:28

well i have been out of math for a few years now… but does h=4x

pie(x)(s)+pie(x)^2=4pie(x)^2 (surface area of cone = surface area of sphere)

pie(x)(s) = 3pie(x)^2 (move the pie(x)^2 over)

s=3x (divide the pie(x) out…?)

h^2 = 3x^2 +x^2 (Pythagorean theorem)

h^2 = 4x^2

h=4x

no clue whats so ever if this is correct ;)

edit: LOL i totally did Pythagorean theorem wrong XD . ehh i should get into a math class

Rich

2011-06-07 11:04:05

From: x[Warrior]x3500
well i have been out of math for a few years now… but does h=4x
How would you get that?

BazzBarrett

2011-06-07 11:10:09

from seeing this question i can see we can work out h through Pythagoras therom as long as we have r and s. Radius (r) = x so we just need to find s.


Start with the equations for surface area:
surface area of a cone = pi x (s + x)
surface area of a sphere = 4 pi x^2
surface area of a circle = pi x^2
area of a hemisphere = 1/2 4 pi x^2 + pi x^2
= 3 pi x^2

make the equations = each other:
pi x (s + x) = 3 pi x^2
rearrange to make s the subject
s + x = 3 pi x^2 / pi x
pi and an x cancel
s + x = 3 x
s = 2x

using Pythagoras:

s^2 = x^2 + h^2
substitute s in:
4x^2 = x^2 + h^2
rearrange to make h the subject:
sqr( 4 x^2 - x^2 ) = h
h = sqr( 3 x^2)

hope that made sence :)

BazzBarrett

2011-06-07 11:11:38

From: x[Warrior]x3500
well i have been out of math for a few years now… but does h=4x

pie(x)(s)+pie(x)^2=4pie(x)^2 (surface area of cone = surface area of sphere)

pie(x)(s) = 3pie(x)^2 (move the pie(x)^2 over)

s=3x (divide the pie(x) out…?)

h^2 = 3x^2 +x^2 (Pythagorean theorem)

h^2 = 4x^2

h=4x

no clue whats so ever if this is correct ;)


right idea :) but "There is a hemisphere and a cone"
not a sphere :P

Huthaifah

2011-06-07 15:30:30

I feel like a noob, lol, we just started Algebra. Anyways, what kind of math are you guys doing, seems kind of crazy….

Rich

2011-06-07 16:07:20

From: BazzBarrett
*SNIP*
hope that made sence :)
Yep, that makes perfect sense. Now I've seen it, it's actually fairly easy. Thanks :)

From: Huthaifah
I feel like a noob, lol, we just started Algebra. Anyways, what kind of math are you guys doing, seems kind of crazy….
EdExcel GCSE Modular (UK).