SRL Archive - Mathematics

Easy stuff.


Sandstorm

2010-10-27 21:32:22

So I have to do some work I haven't thought about in a while, and didn't listen to. Just some applications of systems of equations.

Daniel and Matt are selling cookie dough for a school fundraiser. They're selling sugar cookie dough and oatmeal cookie dough. Daniel sold 12 packages of sugar dough and 8 packages of oatmeal dough for $196. Matt sold 13 packs of sugar dough and 4 packs of oatmeal dough for $161.

Can someone just quickly show me how to set up the equation for this? I can solve it, I just forget that.

*whistles* Now I feel kinda stupid :p.

i luffs yeww

2010-10-27 21:44:21

s = # of sugar cookie packages sold
o = # of oatmeal cookie packages sold

Daniel:

12s + 8o = 196

Matt:

13s + 4o = 161

But here's more to the question than that, so you should include that.

Sandstorm

2010-10-27 21:46:03

What do you mean there's more? All that's left is the question itself (find the cost).

Also, that's what I did and it didn't seem to work D:.

i luffs yeww

2010-10-27 21:47:49

Because that's not a system of equations. It's a single inequality for two people. There's no more to do than that, other than guess and check.. Without more information, that is.

Oh no wait. One sec.

Sandstorm

2010-10-27 21:54:17

Just saying what my teacher told me xP.

i luffs yeww

2010-10-27 21:56:27

12s + 8o = 196

(13s + 4o = 161) * -2

—

12s + 8o = 196

-26s + -8o = -322

—

(-26s = -322) * -1 (just because it's easier, imo.)

—

(26s)/26 = (322)/26

—

s = 161/13

—

12(161/13) + 8o = 196

—

1932/13 + 8o = 196

—

(1932/13) - (1932/13) + 8o = 196

—

(1/8) * (8o) = (616/13) * (1/8)

—

o = 77/13

—

12(161/13) + 8(77/13) = 196

—

(1932/13 + 616/13 = 196)13

—

1932 + 616 = 2548

—

2548 = 2548

Sandstorm

2010-10-27 22:03:51

S = 161/13 = $12.38
O = 77/13 = $5.92

That's all I needed. Thanks!

Hey-o!

In case you look at this again, I need some more help (again, on stuff I didn't listen to xD).

I need to graph a compound inequality after solving it:

49 < -6n + 1 <= -17

I've been searching google, but they all talk about it differently D:.

Edit again! I found it :D.

i luffs yeww

2010-10-27 22:20:32

So you don't need help with that inequality or do you?

Sandstorm

2010-10-27 23:02:06

From: i luffs yeww
So you don't need help with that inequality or do you?


Just to make sure I did it right:


49 < -6n + 1 <= -17

49 < -6n + 1

Reverse it, so it looks better:

-6n + 1 > 49

Remove one, to get -6n by itself.

-6n > 48

Divide by -6.

n > -8

One of the two answers is n > -8.

-6n + 1 <= -17

Remove one to get -6n by itself.

-6n <= -18

Divide by -6 to get N by itself.

n <= -3

N <= -3 and n > -8

N is less than or equal to -3 and greater than -8.

Graph it (can't do it here) - closed dot for n <= -3, open dot for n > -8.

Check:

49 < -6n + 1 <= -17

Choose a number greater than -3, a number lower than -8, and a number that should match the equation.

I'll use -2.

-6(-2) + 1 = 13. Greater than 49? No. Less than -17? No. False.

For the second, -9.

-6(-9) + 1 = 55. Greater than 49? Yes. Less than -17? No. False.

For the third, -5.

-6(-5) + 1 = 31. Greater than 49? No. Less than -17? No. False.

Therefore, the inequality is false, and my answer is false, plus the graph.

I think I did that right. Knowing me I did it totally wrong.

Edit:

Looking at it, I realized that something can't be greater than 49 and less than -17 at the same time, saving me all the trouble of solving it. But I did it to make sure I understand it.

i luffs yeww

2010-10-27 23:05:07

:) Just plug things back in to check.