I'm not clear if you mean
((2^32)/300) + 1 or
(2^(32/300)) + 1
Assuming you mean:
(2^(32/300)) + 1
Remember that:
√x = x^(1/2)
√(x^2) = x^(2/2) = x
So for any value raised to a power that is a fraction, you can rewrite it as a root, where the denominator is the degree of the root (square, cubic, etc), and the numerator is the power of the value inside the root. (I'm bad at explaining things ;) )
So for your problem,
(2^32/300)+1,
=(2^(8/75))+1
=

+ 1
Maybe that's what she wanted, because as YoHoJo pointed out, that's not likely to turn out a whole number or nice fraction.
If you meant the first one [((2^32)/300) + 1], then you basically need to get 300 as a power of two (dunno if you have learned this yet)…
300 = 2^x
x = log2(300)
= 8.289
((2^32)/300) + 1
= ((2^32)/(2^8.289))+1
= 2^(32-8.289) + 1
= 2^23.711 + 1
Although this is probably even more decimal-y than the other one ;)