3Garrett3
2009-11-05 16:50:56
Hey guys, once again I am stuck on a question.
Without any further small talk, here it is.
I am thinking that it makes it less spontanious, but I have no real reason why. Can anyone explain this to me?
Without any further small talk, here it is.
For the process:
CH6(l) -> C6H6(s)
The standard entropy and enthalpy changes are:
*Delta*H = -9.83 KJ/mol and *Delta*S = -35.2 J K-1 Mol -1
Predict and explain the effect of an increase in the temperature on the spontaneity of the process
I am thinking that it makes it less spontanious, but I have no real reason why. Can anyone explain this to me?