SRL Archive - News and General

Crack This.


R0b0t1

2008-01-31 21:56:04

Which you won't be able to do, unless you have lots of time and a few super computers, or happen to know a professional cryptanalyst.

To prove you have won, you must enter a series of letters after a certain word… Or post the whole thing. W/E.

Clue sets:

1) 2.31 * 10^71
2) 54. Jokers.

Message: MXYMXKUEZWRPMOHFGPZYGTUTCXSSHB

P1nky

2008-01-31 22:21:02

sp0rky probally could ;p

btw winner gets anything hehe?

footballjds

2008-01-31 22:26:48

don't get wtf to do but w/e?

R0b0t1

2008-01-31 22:28:00

Goddam! No Hehe's!


Well, I don't have anything as of yet, but the people who really want to do something like this most likely want a reward, but I could dig up something.



EDIT: You are supposed to find what the message's plaintext is.

BobboHobbo

2008-02-01 00:02:20

From: R0b0t1
Goddam! No Hehe's!


Well, I don't have anything as of yet, but the people who really want to do something like this most likely want a reward, but I could dig up something.



EDIT: You are supposed to find what the message's plaintext is.


LOL #@C#$#$ "HEHE" block that word its so fking annoying.

Dark_Sniper

2008-02-01 00:31:42

how big of a .txt would this be if it was decoded.

SKy Scripter

2008-02-01 01:21:31

does this site http://schneier.com/solitaire.html have anything to do with it? :confused:

R0b0t1

2008-02-01 17:00:11

Might… :P

It would be the same number of char's as the crypted.

SKy Scripter

2008-02-01 18:46:38

From: R0b0t1
Might… :P

It would be the same number of char's as the crypted.


in that case i could have figured it out by now.. but im too lazy… :p

footballjds

2008-02-01 19:08:31

From: SKy Scripter
in that case i could have figured it out by now.. but im too lazy… :p


not really, cause he'd have to give you the numbers and shit…

richk1693

2008-02-01 19:40:54

Did you make this code up yourself or did you find it on bobscoolcodes.iamawebsite?

P1nky

2008-02-01 21:01:01

can i ask ….
how do you crack that????

or ecrypted scripts :P TEACH ME!

Widget

2008-02-01 21:34:09

Is they key embedded in the string?

So far the best I've been able to get is
KAGGQJSTHEKOKJLNBOXBMBNSCXSSHB

It has Box and The in it :p

richk1693

2008-02-01 22:27:49

From: Widget!
Is they key embedded in the string?

So far the best I've been able to get is
KAGGQJSTHEKOKJLNBOXBMBNSCXSSHB

It has Box and The in it :p

Mind enlightening the rest of us where that came from?

goider

2008-02-01 22:50:43

if you used solitaire (i read the whole page)

that will be a mother of a code to crack…

Sir R. M8gic1an

2008-02-02 02:51:04

i also just read the whole page. even if you do have the key you will still take a whole afternoon. Without the key i'll have grandchildren before you decipher this :/ (and i'm still 16!)

~RM

Freddy1990

2008-02-02 03:30:00

I posted a challenge like this on a site with experts on this kinda stuff once, developed the algorithm myself (I used to love macking encryption algorithms) and they never did crack it :)
I'd give it a go, but I'm rather busy atm, maybe I'll have a shot at it later

Daniel.Blaze

2008-02-02 07:54:32

sounds interesting, i might give it a shot

Miitchyy

2008-02-02 09:20:43

The box of cards is empty?

lol I'm gonna guess

Jackrawl

2008-02-02 12:02:02

Hehe, I know the answer.

GoF

2008-02-02 12:10:34

From: JackLKrawl
Hehe, I know the answer.


Hehe, that's cool. Sooooooo… Did you just like google "cool uber encryption stuffz" and put some text in some box and boom => encrypted or make it up yourself :D.. Ahihi.

R0b0t1

2008-02-02 13:01:58

No, you can simply substitute a word, such as the, for every contiguous segment and substitute letters accordingly.


This only works because the message is so small, because usually you'd need a much bigger word and a computer program, unless you wanted to do it by hand…


This'll work for every message that uses 26 letters, and no bit shifting etc.

Jackrawl

2008-02-02 13:18:41

From: GoF
Hehe, that's cool. Sooooooo… Did you just like google "cool uber encryption stuffz" and put some text in some box and boom => encrypted or make it up yourself :D.. Ahihi.


I'm going to be mysterious and say yes to a question that is clearly not yes or no.

GoF

2008-02-02 14:13:36

From: JackLKrawl
I'm going to be mysterious and say yes to a question that is clearly not yes or no.


I asked Roebawt, not you.

R0b0t1

2008-02-02 15:59:01

Oh, if you were asking me, pretty much. 'Cept I knew what I was looking for.

P1nky

2008-02-02 15:59:09

jack so you cracked it right?

R0b0t1

2008-02-02 16:24:34

Not likely, he hasn't tried to contact me about it…

IEatJ00erBaybees

2008-02-02 16:36:24

…Still wondering how you guys do this stuff…

Jackrawl

2008-02-02 18:43:00

From: R0b0t1
Not likely, he hasn't tried to contact me about it…


Thats because my internet sucks so bad that I get a choke of 9-18 in CS, with a loss of 4….

R0b0t1

2008-02-02 18:50:41

Yeah, yeah, thats what they all say :p.

Jackrawl

2008-02-02 19:09:59

From: R0b0t1
Yeah, yeah, thats what they all say :p.


I really do, but the reason I haven't sent it to you yet is because I'm trying to make a SCAR "Decoder."

R0b0t1

2008-02-02 20:04:35

You mean you are making a SCAR Solitare script, or you are using a letter substitution thingy?

bullzeye95

2008-02-02 21:19:43

Will be very fast if it's made in scar :rolleyes:

Jackrawl

2008-02-02 23:28:23

From: R0b0t1
You mean you are making a SCAR Solitare script, or you are using a letter substitution thingy?


Whats the difference?
Anyway, it's pretty much impossible to do a 'letter substitution thingy' unless I make it write all the results, which can be thousands…

R0b0t1

2008-02-03 12:33:29

Letter substitution = cracker

No, its not, actually. Just do a letter count… Say if there are more K's and X's than E's and T's, you know its wrong. Just output the variants that have acceptable letter counts, which might be about 3ish for different types of encryption… because for mine, you'd need two messages w/ same key or lots of math knowledge.

Jackrawl

2008-02-05 16:16:56

From: R0b0t1
Letter substitution = cracker

No, its not, actually. Just do a letter count… Say if there are more K's and X's than E's and T's, you know its wrong. Just output the variants that have acceptable letter counts, which might be about 3ish for different types of encryption… because for mine, you'd need two messages w/ same key or lots of math knowledge.


Not necessarily.
B can equal A, C can Equal H. You'd need human logic in there..a vocabulary.