SRL Archive - Java Help and Tutorials

I tried Integer.parseInt but it's not working for my name meh.. here is the code

public int[] intDigits(long Int) 
	{
		String s;
		int [] result;
		s = Long.toString(Int);
		for (int i = 0; i < s.length(); i++)
		{
			result[i] = Integer.parseInt(s[(i + 1)]);
		}
		return result;
	}

From: Officer Barbrady
I tried Integer.parseInt but it's not working for my name meh.. here is the code

public int[] intDigits(long Int) 
	{
		String s;
		int [] result;
		s = Long.toString(Int);
		for (int i = 0; i < s.length(); i++)
		{
			result[i] = Integer.parseInt(s[(i + 1)]);
		}
		return result;
	}

String str = "12345";
int[] array = new int[str.length()];
for (int i = 0; i < array.length; i++) {
    array[i] = Integer.parseInt(str.substring(i, i + 1));
}

From: CynicRus

String str = "12345";
int[] array = new int[str.length()];
for (int i = 0; i < array.length; i++) {
    array[i] = Integer.parseInt(str.substring(i, i + 1));
}

Ahh ok so I have to create a new int object array or something

Not tested. Not the fastest. but this works well in my head.

public int[] intDigits(long nr) 
    {
        int amountOfDigits = Math.floor(Math.log10(nr)) + 1; //yes, math.floor + 1 instead of math.ceil 
        int [] result;
        for (int i = amountOfDigits; i > 0; i--)
        {
            result[i] = Math.floor(nr / Math.pow(10, i));
            nr -= result[i] * Math.pow(10, i);
        }
        return result;
    }

From: Officer Barbrady
I tried Integer.parseInt but it's not working for my name meh.. here is the code

public int[] intDigits(long Int) 
	{
		String s;
		int [] result;
		s = Long.toString(Int);
		for (int i = 0; i < s.length(); i++)
		{
			result[i] = Integer.parseInt(s[(i + 1)]);
		}
		return result;
	}

Use String.charAt() to retrieve the character at a specific index. This is the proper way in Java.